Varianta 1 - 2009



Subiectul I


A.

1. tripla
2. doi
3. CHCl3
4. tioaminoacid
5. apa


B.

1. a
2. c
3. b
4. c
5. b




C.

1.

Compusul este un compus aromatic; Contine grupele functionale iodo- (I), hidroxil de tip fenol (-OH legat de nucleul benzenic), carboxil (-COOH) si amino (-NH2)

2.

F.M: C9H9O3NI2
M= 9*12 + 9 + 14+ 3*16+2*127 = 433
p=1400/433 = 3,23 % N

3.

C1: primar
C2: secundar


5.

n C2H6O = 0,25 moli
M = 2*12+6+16=46
M= 46*0,25=11,5




Subiectul III


G1.

2.

nC6H6=4x
M=6*12+6 = 78
4x=20; x=5 kmoli

MC6H5NO2 = 6*12+5+14+2*16 =123
m = 5*123 = 615 kg = 0,615 t

4.

F.M: C10H8
M = 10*12+8 =128

120 g C…..8 g H….. 128g C10H8
a………………b……… 100 g C10H8

a=12000/128 = 93,75% C
b = 800/128 = 6,25% H


G2.

1.

Nitrarea se face cu un amestec de HNO3 concentrat si H2SO4 concentrat (amestec sulfonitric)

3.

mC10H8 pura = 0,8*1,6 = 1,28t
nC10H8 = 1280/128 =10 kmoli

100 kmoli C10H8………..90 kmoli C10H7NO2
10 kmoli C10H8……………….x

X=9 kmoli C10H7NO2
m=9*173=1557 kg = 1,557 t