Varianta 3 - 2009



Subiectul I


A.

1. neopentanul
2. legaturi de hidrogen
3. mare
4. nesaturat
5. usor solubila


B.

1. d
2. b
3. d
4. c
5. b




C.

2.

F.M: C10H12NO2Cl
M = 10*12+12+14+2*16+35,5 =213,5
P= 3550/213,5 = 16,63% Cl

3.

C1: tertiar
C2: secundar


5.

n NaOH = 0,15 moli
M = 23+16+1 = 40

md = 40*0,15 = 6 g NaOH
c=100md/ms
ms=100md/c

mNaOH = 600/20 = 30 g



Subiectul III


G2.

2.

n C6H6O = 12x
M = 12*6+6+16 = 94
n C6H6O = 846/94 = 9 kmoli
12 x =9; x=0,75 kmoli

n HNO3 = 16 x kmoli; n=16*0,75=12 kmoli
M HNO3= 1+14+3*16 = 63
md HNO3 = 63*12=756 kg
ms=100md/c ms=75600/63 = 1200 kg = 1,2 t solutie

3.

n C6H5NO3 = 4*0,75 = 3 kmoli
Cu = 300/9 = 33,33%
Nt =27/4 kmoli
Ct = 27*25/9 = 75%